How to decide the ratio of solvent to be used in liquid liquid extraction? - solvent can clipart
How it is decided that the ratio of 1:1 or solvent must double or triple the solution in the liquid-liquid extraction. If I will be up to 10 ml of 5 mg of naphthalene in water to take, how can I when a 1:1 ratio sufficient to eliminate all the middle of naphthalene when my hexane solvent?
Wednesday, February 3, 2010
Solvent Can Clipart How To Decide The Ratio Of Solvent To Be Used In Liquid Liquid Extraction?
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To determine the necessary relationship for determining the payout ratio of naphthalene between the organic phase (hexane) and aqueous (water) is required. Naphthalene probably much more soluble in hexane than in water.
To measure this relationship can take a defined volume of a solution of naphthalene dissolved in water and with an equal volume of hexane. The two liquids are shaken in five minutes, then allowed the two liquids are separated into two layers.The hexane has a density of about 0.66 g / cm 3 as a topcoat. Measuring the concentration of naphthalene in both liquids. It should facilitate the monitoring of naphthalene in water and a much higher concentration in hexane.
The ratio of the concentration of hexane in the organic phase by the concentration of water in equilibrium is broken, the payout ratio. This could be anywhere from 2 to 2000, and I have no idea what it is in this case. Let, s go out just like this, it is 99:1.
After about 1 g of naphthalene dissolved in a certain amount of WatER distributed in an equal volume of hexane, in order to stay at 0.01 g in water and 0.99 g in hexane. (0.99 / 0.01 = 99)
Now, using ten volumes of water to a volume of hexane. Naphthalene also distributed so that (Co) / (Ca) = 99, for example, the concentration remains the same ratio. But Va / Vo = 10
Thus, 0.1 g of naphthalene remained in the aqueous phase and 0.9 g in the organic phase. So I do not want all the naphthalene in the kidnapping of a separate and escape to the aqueous phase and re-add the same volume of hexane extract of fresh and new. This then will reduce the concentration of naphthalene in water to 0.01 grams, but now is only 20% of the volume of hexane in the first case, to obtain the same result.
Once you have a payout ratio of Mathematics at the plant.
You need to know the distribution coefficient for that. The general principle is that the extraction of more effective several times with the lowest proportion is as a single extraction with a larger share.
In other words, the same amount of solvent in small portions as often as you give a better extraction.
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